Answer:
Explanation:
Given data:
Initial temperature = 295 K
Initial volume = 1.0 L
Values of A,B, C and D.
Solution:
As it is mentioned in question V₁ and T₁ are the first readings of table thus,
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
For A:
V₁/T₁ = V₂/T₂
1.0 L / 295 K = 1.3 L /T₂
T₂ = 1.3 L × 295 K / 1.0 L
T₂ = 383.5 K
For B:
V₁/T₁ = V₂/T₂
1.0 L / 295 K = V₂ /250 k
V₂ = 1.0 L × 250 k/ 295 K
V₂ = 250 k.L/ 295 K
V₂ = 0.85 L
For C:
V₁/T₁ = V₂/T₂
1.0 L / 295 K = V₂ /325 k
V₂ = 1.0 L × 325 k/ 295 K
V₂ = 325 k.L/ 295 K
V₂ = 1.1 L
For D:
V₁/T₁ = V₂/T₂
1.0 L / 295 K = 0.75 L /T₂
T₂ = 0.75 L × 295 K / 1.0 L
T₂ = 221.25 K
