Answer:
The value of new pressure will be 1.56 atm.
Explanation:
Using combined gas law :
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 2.4 atm
[tex]P_2[/tex] = final pressure of gas = ?
[tex]V_1[/tex] = initial volume of gas = [tex]6 L[/tex]
[tex]V_2[/tex] = final volume of gas = 15 L
[tex]T_1[/tex] = initial temperature of gas = [tex]400 K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]650 K[/tex]
Now put all the given values in the above equation, we get:
[tex]\frac{2.4 atm \times 6 L}{400 K}=\frac{P_2\times 15 L}{650 K}[/tex]
[tex]P_2=\frac{2.4 atm \times 6 L\times 650 K}{400 K\times 15 L}[/tex]
[tex]P_2=1.56 atm[/tex]
The value of new pressure will be 1.56 atm.
