Answer:
Force applied will be equal to 5625000 N
Explanation:
We have given mass of the automobile m = 900 kg
Initial velocity of the automobile u = 54 km/hr
As 1 km = 1000 m and 1 hour = 3600 sec
So [tex]54km/hr=54\times \frac{5}{18}=15m/sec[/tex]
As the automobile finally stops so final velocity v = 0 m/sec
Distance after which automobile stops s = 1.8 cm = 0.018 m
From third equation of motion [tex]v^2=u^2+2as[/tex]
[tex]0^2=15^2+2\times a\times 0.018[/tex]
[tex]a=-6250m/sec^2[/tex]
From newtons force on any object is equal to F = ma
So force [tex]F=900\times 6250=5625000N[/tex]
So force applied will be equal to 5625000 N
