The frictional force between the block and the surface is 6 N
Explanation:
We can solve this problem by applying Newton's second law of motion, which states that the net force on an object is equal to the product between its mass and its acceleration:
[tex]F_{net}=ma[/tex]
where
[tex]F_{net}[/tex] is the net force
m is the mass
a is the acceleration
For the block in this problem, we have:
[tex]a=0[/tex], because its acceleration is zero
[tex]F_{net}=F_a-F_f[/tex], since the net force is given by the difference between the applied force [tex]F_a[/tex] (in the forward direction) and the frictional force [tex]F_f[/tex] (in the backward direction)
Therefore Newton's second law becomes
[tex]F_a-F_f = ma = 0[/tex]
Which means
[tex]F_f=F_a[/tex]
And since the applied force is [tex]F_a=6 N[/tex], this means that the friction force is also 6 N:
[tex]F_f=F_a=6 N[/tex]
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