Answer:
a) 1/4
b) 1/8
c) 1/64
Explanation:
Let's assume that the allele "a" is responsible for albinism. The genotype of carrier parents would be "Aa".
a) Aa x Aa = 1/4 AA (Normal): 1/2 Aa (normal) : 1/4 aa (albinic)
Therefore, the probability that their next child will be albino is 1/4
b) In each reproduction, the proportion of a girl child= XX x XY= 1/2 XX (girl) : 1/2 XY (boy)
And the chances of getting an affected child = Aa x Aa= 1/4 AA (Normal): 1/2 Aa (normal) : 1/4 aa (albinic)
Therefore, the probability that their next child will be an albino girl= 1/2 (girl) x 1/4 albinic= 1/8
c) In each reproduction, the chances of getting an affected child = Aa x Aa= 1/4 AA (Normal): 1/2 Aa (normal) : 1/4 aa (albinic).
The chances that their next three children will be albino= 1/4 x 1/4 x 1/4 = 1/64
