Answer:
Explanation:
Given
emmisivity of spacecraft [tex]\epsilon =0.6[/tex]
absorptivity [tex]\alpha =0.2[/tex]
Solar radiation incident [tex]q_{rad}=2100\ W/m^2[/tex]
heat Absorbed by spacecraft is
[tex]Q_{absorbed}=\alpha A_sq_{rad}[/tex]
where [tex]A_s=[/tex]Surface area of Sphere
[tex]Q_{absorbed}=0.2\times A_s\times 2100[/tex]
[tex]Q_{absorbed}=420A_s[/tex]
Radiation emitted by spacecraft
[tex]Q=\epsilon \sigma A_sT^4[/tex]
When the radiation emitted equals to the solar energy absorbed
[tex]Q_{absorbed}=Q[/tex]
[tex]420A_s=\epsilon \sigma A_sT^4[/tex]
[tex]420=0.6\times 5.67\times 10^{-8}\times T^4[/tex]
[tex]T_s=3.333\times 100=333.33\ K[/tex]
