Answer:
Distance =0.5 m
Explanation:
We have given time the pot takes to fall a distance
y-y₀=1.9m
And Gravity g=9.8m/s²
From this we can calculate the velocity of the pot when
it just reached the top of the window.take positive y direction to be downward
[tex]y-y_{o}=v_{o}t+(1/2)gt^{2} \\ v_{o}=\frac{y-y_{o} -1/2gt^{2} }{t}\\ v_{o}=\frac{(1.9)-(4.9*0.38^{2} )}{0.38}\\ v_{o}=3.138m/s[/tex]
The flowerpot falls from rest and we have velocity it gain until it reaches the top of the window below,From this information we can find distance between the sill and the top of the window as:
[tex]v^{2}=(v_{o})^{2}+2g(y-y_{o} )\\ (y-y_{o} )=\frac{v^{2}-v_{o}}{2g}\\ (y-y_{o} )=\frac{(3.138)^{2}-0}{2(9.8)}\\ (y-y_{o} )=0.5m[/tex]
