Answer:
t = 1.58 s
Explanation:
given,
Speed of ranger, v = 56 km/h
v = 56 x 0.278 = 15.57 m/s
distance, d = 65 m
deceleration,a = 3 m/s²
reaction time = ?
using stopping distance formula
[tex]d = v. t + \dfrac{v^2}{2a}[/tex]
[tex]t = \dfrac{d}{v} -\dfrac{v}{2a}[/tex]
t is the reaction time
[tex]t = \dfrac{65}{15.57} -\dfrac{15.57}{2\times 3}[/tex]
t = 1.58 s
hence, the reaction time of the ranger is equal to 1.58 s.
