Answer:
Explanation:
Given
Average Electric Field Strength [tex]E=100\ N/C[/tex]
Considering charge distribution to be uniform and earth to be symmetrical
Using Gauss law
[tex]\phi =\oint \vec{E}\cdot \vec{dA}[/tex]
[tex]\phi =E\cdot A_{sphere}[/tex]
Also [tex]E\cdot A_{sphere}=\frac{Q_{inside}}{\epsilon }[/tex]
here Electric Field is acting inward therefore
[tex]Q=-\epsilon EA_{sphere}[/tex]
[tex]Q=-8.85\times 10^{-12}\times 100\times 4\pi \times (6.37\times 10^6)^2[/tex]
[tex]Q=-4.51\times 10^5\ C[/tex]
Answer:
D The strength of the field increases as you get closer to Earth, as shown by the smaller spaces between the circles.
Explanation:
