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A gas storage tank has a volume of 3.5 X 105 L when the temperature is 27oC, and the pressure is 101 kPa. What is the new volume of the tank if the temperature drops to -10oC and the pressure drops to 95 kPa ?

Respuesta :

Eduard22sly

Answer: 3.26x10^5L

Explanation:

P1 = 101kPa

P2 = 95kPa

T1 = 27°C = 27 +273 =300k

T2 = —10°C = —10 +273 = 263k

V1 = 3.5 x 10^5 L

V2 =?

P1V1 / T1 = P2V2 /T2

(101 x 3.5 x 10^5)/300 = (95xV2)/263

300x95xV2 = 101x 3.5x10^5x263

V2 = (101x 3.5x10^5x263) /(300x95)

V2 = 3.26x10^5L

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