An unknown element is found to contain isotopes with the following masses and natural abundances: 38.9637 amu (93.08%), 39.9640 amu (0.012%), and 40.9618 amu (6.91%). Using these data, identify the element. a. S b. K c. Cld. Ca e. Ar

Respuesta :

Answer:

b. K

Explanation:

The formula for the calculation of the average atomic mass is:

[tex]Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})+(\frac {\%\ of\ the\ third\ isotope}{100}\times {Mass\ of\ the\ third\ isotope})[/tex]

Given that:

For first isotope:

% = 93.08 %

Mass = 38.9637 amu

For second isotope:

% = 0.012 %

Mass = 39.9640 amu

For third isotope:

% = 6.91 %

Mass = 40.9618 amu

Thus,  

[tex]Average\ atomic\ mass=\frac{93.08}{100}\times {38.9637}+\frac{0.012}{100}\times {39.9640}+\frac{6.91}{100}\times {40.9618}=36.26741196+0.00479568+2.83046038=39.1027\ amu[/tex]

Average atomic mass = 39.1027 amu

This mass corresponds to b. K Potassium.

Answer: The unknown element is potassium.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

[tex]\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i[/tex] .....(1)

  • For isotope 1:

Mass of isotope 1 = 38.9637 amu

Percentage abundance of isotope 1 = 93.08 %

Fractional abundance of isotope 1 = 0.9308

  • For isotope 2:

Mass of isotope 2 = 39.9640 amu

Percentage abundance of isotope 2 = 0.012 %

Fractional abundance of isotope 2 = 0.00012

  • For isotope 3:

Mass of isotope 3 = 40.9618 amu

Percentage abundance of isotope 3 = 6.91 %

Fractional abundance of isotope 3 = 0.0691

Putting values in equation 1, we get:

[tex]\text{Average atomic mass of Z}=[(38.9637\times 0.9308)+(39.9640\times 0.00012)+(40.9618\times 0.0691)][/tex]

[tex]\text{Average atomic mass of Z}=38.85amu[/tex]

For the given options:

Option a: Average atomic mass of Sulfur = 32.065 amu

Option b: Average atomic mass of Potassium = 39.09 amu

Option c: Average atomic mass of Chlorine = 35.45 amu

Option d: Average atomic mass of Calcium = 40.078 amu

Option e: Average atomic mass of Argon = 39.94 amu

As, the average atomic mass of unknown element is near to the average atomic mass of potassium. So, the unknown element is potassium.

Hence, the unknown element is potassium.