Answer:
13.01 m/s²
Explanation:
The period of a simple pendulum is given as
T = 2π√(L/g) .......................... Equation 1
Where T = Period of the simple pendulum, L = Length of the pendulum, g = acceleration due to gravity of the planet.
Given; T = 132/103 = 1.28 s, L = 54 cm = 0.54 m, π = 3.14
Substitute into equation 1
1.28 = (2×3.14)√(0.54/g)
1.28 = 6.28√(0.54/g)
Making g the subject of the equation,
√(0.54/g) = 1.28/6.28
√(0.54/g) = 0.2038
0.54/g = (0.2038)²
0.54/g = 0.0415
g = 0.54/0.0415
g = 13.01 m/s²
Hence the value of the acceleration due to gravity on the planet = 13.01 m/s²
