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Two light bulbs, A and B, are connected to a 120-V outlet (a constant voltage source). Light bulb A is rated at 60 W and light bulb B is rated at 100 W. Which light bulb has a greater filament resistance?

Respuesta :

asuwafoh

Answer:

Bulb A has a greater resistance.

Explanation:

Electric power (P) = V²/R

P = V²/R................ Equation 1

Where P = power, V = Voltage, R = Resistance.

Make R the subject of the equation

R = V²/P ................ Equation 2

For Bulb A,

Given: V = 120 V, P = 60 W.

Substitute into equation 2

R = 120²/60

R = 240 Ω

For bulb B

Given: V =120 V, P = 100 W.

Substitute into equation 2

R = 120²/100

R = 14400/100

R = 144 Ω

Hence Bulb A has a greater resistance.

asuwafohjames

bulb A has the greater filament resistance.

What is resistance?

This can be defined as the ability of a conducting material to oppose the flow of electric current.

To know the bulb with the greatest filament resistance, we use the formula below.

Formula:

  • P = V²/R................. Equation 1

making R the subject of the equation

  • R = V²/P............... Equation 2

Where:

  • P = power of the bulb
  • V = Outlet voltage
  • R = Resistance of the filament.

For Bulb A,

Given:

  • P = 60 W
  • V = 120 V

Substitute these values into equation 1

  • R = (120²)/60
  • R = 240 ohms.

For Bulb B,

Given:

  • P = 100 W.
  • V = 60 V

Substitute these values into equation 1

  • R = (120²)/100
  • R = 144 ohms.

Hence, From the above, it can be seen that bulb A has the greater filament resistance.

Learn more about resistance here: https://brainly.com/question/13735984

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