Respuesta :
Answer:
[tex]6x+7y+3=0[/tex]
Step-by-step explanation:
We are asked to find the equation of the line in general form, which has a of -6/7 and containing the point (10,-9).
We know that genera equation of a line is in form [tex]Ax+By+C=0[/tex], where, A, B and C are real numbers.
First of all, we will write our equation in point-slope form as:
[tex]y-y_1=m(x-x_1)[/tex], where,
m = Slope of line,
[tex](x_1,y_1)[/tex] = Given point on line.
[tex]y-(-9)=-\frac{6}{7}(x-10)[/tex]
[tex]y+9=-\frac{6}{7}x+\frac{60}{7}[/tex]
[tex]y*7+9*7=-\frac{6}{7}x*7+\frac{60}{7}*7[/tex]
[tex]7y+63=-6x+60[/tex]
[tex]6x+7y+63-60=-6x+6x+60-60[/tex]
[tex]6x+7y+3=0[/tex]
Therefore, our required equation would be [tex]6x+7y+3=0[/tex].
