On a certain hot​ summer's day, 391 people used the public swimming pool. The daily prices are $1.25 for children and $2.25 for adults. The receipts for admission totaled $752.75. How many children and how many adults swam at the public pool that​ day?

Respuesta :

Number of children swam at public pool = $127

Number of adults swam at public pool = $264

Solution:

Given daily price for children = $1.25

Daily price for adults = $2.25

Total price of admission = $752.75

Let x be the number of children and y be the number of adults.

Total number of people used swimming pool = 391

⇒ x + y = 391 – – – – (1)

Total price of admission = $752.75

⇒ 1.25 x + 2.25 y = 752.75 – – – – (2)

Solve the equation (1) and (2):

Multiply equation (1) by 2 and

(1) × 2 ⇒  1.25 x + 1.25 y = 488.75

Now, subtract it from equation (2)

⇒ 1.25 x + 2.25 y – (1.25 x + 1.25 y) = 752.75 – 488.75

⇒ 1.25 x + 2.25 y – 1.25 x – 1.25 y = 752.75 – 488.75

Combine like terms together.

⇒ 1.25 x – 1.25 x + 2.25 y  – 1.25 y = 752.75 – 488.75

y = 264

Substitute y = 264 in equation (1)

⇒ x + 264 = 391

⇒ x = 391 – 264

x = 127

Number of children swam at public pool = $127

Number of adults swam at public pool = $264