Respuesta :
Answer:
(a) At 5% significance level, reject H0
At 1% significance level, reject H0
(b) At 5% significance level, fail to reject H0
At 1% significance level, fail to reject H0
Step-by-step explanation:
(a) The test is a one tailed test
At 5% significance level, the critical value is 1.645
Conclusion: Reject H0 because the test statistic -1.78 is less than the critical value 1.645
At 1% significance level, the critical value is 2.326
Conclusion: Reject H0 because the test statistic -1.78 is less than the critical value 2.326
(b) The test is a two tailed test
At 5% significance level, the critical value is 1.96. The region of no rejection of H0 lies between -1.96 and 1.96
Conclusion: Fail to reject H0 because the test statistic -1.78 falls within -1.96 and 1.96
At 1% significance level, the critical value is 2.576. The region of no rejection of H0 lies between -2.576 and 2.576
Conclusion: Fail to reject H0 because the test statistic falls within -2.576 and 2.576
The conclusion that can be made from an hypothesis test depends on
the significance level and p-value.
Response:
(a) The conclusion at 5% is there is statistical evidence to suggest that p < 0.65
At 1% level; fail to reject H₀: p = 0.65, there is statistical evidence to suggest that p = 0.65
(b) With Hₐ ≠ 0.65, the conclusion at the 5% significance level is that there is sufficient statistical evidence that p = 0.65
At the 1% level, fail to reject H₀: p = 0.65,
Which is the method to draw conclusion from an hypothesis test?
The null hypothesis, H₀: p = 0.65
The alternative hypothesis, Hₐ: p < 0.65
The z-score is z = -1.78, which gives;
The p-value = 0.0375
(a) The significance level is 5%
Which gives, α = 0.05
Given that the p-value is less than the significant level, we have that
there is sufficient evidence against the null hypothesis, given that the
probability that the null hypothesis is correct is less than the significant
level of 5%.
Therefore, reject H₀, p = 0.65
- There is sufficient statistical evidence to suggest that the the p is less than 0.65, (p < 0.65)
However, at 1% significant level, α = 0.01, and the p-value, p = 0.0375 is
larger than the significance level.
- Therefore, we fail to reject the null hypothesis and there is sufficient statistical evidence to suggest that p = 0.65
(b) Hₐ: p ≠ 0.65
We have;
[tex]\alpha = \dfrac{5 \%}{2} = 2.5 \% = \mathbf{0.025}[/tex]
Which gives;
The p-value (0.0375) is larger than the significant level, therefore, we
fail to reject the null hypothesis.
- There is sufficient statistical evidence to suggest that p = 0.65
At the 1% level of significance, we have;
[tex]\alpha = \dfrac{1 \%}{2} = 0.5 \% = 0.005[/tex]
Which gives;
The p-value at z = -1.78 (p = 0.0375) is larger than the significant level
Therefore;
- There is sufficient evidence to suggest that p = 0.65
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