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A cylindrical shell of radius 7.1 cm and length 251 cm has its charge density uniformly distributed on its surface. The electric field intensity at a point 25.2 cm radially outward from its axis (measured from the midpoint of the shell ) is 37400 N/C.(a) What is the net charge on the shell?
(b) What is the electric field at a point 4.07 cm from the axis? The value of Coulomb’s constant is 8.99 × 10^9 N • m^2/C^2.

Respuesta :

boffeemadrid

Answer:

0.00000131569788654 C

0

Explanation:

R = Radius = 7.1 cm

L = Length of shell = 251 cm

r = 25.2 cm

E = Electric field = 37400 N/C

Electric field is given by

[tex]E=\dfrac{2kq}{rL}\\\Rightarrow q=\dfrac{ErL}{2k}\\\Rightarrow q=\dfrac{37400\times 0.252\times 2.51}{2\times 8.99\times 10^{9}}\\\Rightarrow q=0.00000131569788654\ C[/tex]

The net charge on the shell is 0.00000131569788654 C

Here, 4.07<7.1 cm which means r'<R

From Gauss law the electric at that point is 0

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