127 children and 264 adults swam at the public pool that day
Solution:
Let "c" be the number of children swam
Let "a" be the number of adult swam
Cost for each children = $ 1.25
Cost for each adult = $ 2.25
391 people used the public swimming pool
Therefore,
c + a = 391
a = 391 - c ------- eqn 1
The receipts for admission totaled $752.75
Therefore, we frame a equation as:
number of children swam x Cost for each children + number of adult swam x Cost for each adult = 752.75
[tex]c \times 1.25 + a \times 2.25 = 752.75[/tex]
1.25c + 2.25a = 752.75 ---------- eqn 2
Let us solve eqn 1 and eqn 2
Substitute eqn 1 in eqn 2
1.25c + 2.25(391 - c) = 752.75
1.25c + 879.75 - 2.25c = 752.75
c = 879.75 - 752.75
c = 127
Substitute c = 127 in eqn 1
a = 391 - 127
a = 264
Thus 127 children and 264 adults swam at the public pool that day
