Answer:
Explanation: Where binary numbers are made up of 0s and 1s, numbers in hexadecimal (base 16) contains digits from 0 to 9 as well as letters from A to F. Any number gotten from applying the placeholders (8,4,2,1) that is above 9 is changed into letters. Thus: 10 = A; 11 = B; 12 = C; 13 = D; 14 = E & 15 = F
Solving the question, we split the binaries groups of fours while adding 0s from the left hand side of incomplete groups of four to make it up to four.
I would place the placeholders in brackets for example 1(8) should be read as "number of 8s is 1; 0(2) as " number of 2s is 0"
1. 1101 in base to to base 16 = 1(8) 1(4) 0(2) 1(1)
= 8 + 4 + 0 + 1 = 13 = D
Therefore, 1101 base 2 is D in hexadecimal
2. 11101110 = 1110 & 1110 {group of four}
1110 = 1(8) 1(4) 1(2) 0(1)
= 8 + 4 + 2 + 0 = 14 = E
Therefore, 11101110 base 2 = EE in hexadecimal
