Answer:
The velocity of the object 1 s after it is dropped is -9.8 m/s.
Explanation:
Hi there!
The instantaneous velocity is defined by the change in height over a very small time. Mathematically, it is expressed as the derivative of the function h(t):
instantaneous velocity = dh/dt
dh/dt = h´(t) = -2 · 4.9 · t
h´(t) = -9.8 · t
Now we have to eveluate the function h´(t) at t = 1 s:
h´(1) = -9.8 · (1) = -9.8
The velocity of the object 1 s after it is dropped is -9.8 m/s.
