Answer:
a.p=0.177
b.0.296
c. 0.463
D. 0.066
Explanation:
Since black fur is dominant over white fur, we say
probability of giving back to offsprings with blackfur=75%
whitefur offspring is 25%
All with black fur
P=[tex]^{n} C_{r} B^{r} W^{n-r}[/tex]
P=6C6*.75^6*0.25^(6-6)
P=0.177*1*1
p=0.177
b) Four with black fur and two with white fur
6C4*0.75^4*0.25^2
0.296
cc) At least two of the pups having white fur
if two of the pups have at least white fur
the combinations will be
6C4*0.75^4*0.25^2+6C3*0.75^3*0.25^3+6C2*0.75^2*0.25^4+6C1*0.75^1*0.25^5+6C6*0.75^0*0.25^6
0.296+0.131+0.032+0.0043+0.0002
0.463
d. The firstborn pup with white fur, and among the remaining five pups, three with black fur and two with white fur.
6C5(0.75)^5*0.25^1*5C3*.75^3+0.25^2
p=0.066
