Respuesta :

PSN03

Yo sup??

Since there is an x^2 term therefore this equation is of a parabola

By taking LCM and then cross multiplying it.

6y=x^2-9x+26

6y=x^2-9x+(9/2)^2+23/4

6y-23/4=(x-9/2)^2

we see that this is of the form

X^2=4AY

(x-9/2)^2=4(3y/2-23/16)

Hope this helps.

Answer:

[tex]f(x) =- \sqrt{x-1}+3[/tex]

Step-by-step explanation:

This looks like a square root function [tex]f(x) = \sqrt{x}[/tex]  but symmetric with respect to the x axis and shifted to the right for 1 and up for 3:

Lets take  [tex]f(x) = \sqrt{x}[/tex] . The function symmetric with respect to the x axis would be [tex]-f(x)[/tex], so now we have:

                                                [tex]f(x) = -\sqrt{x}[/tex]

Lets take [tex]f(x) = -\sqrt{x}[/tex] and shift it up for y = 3. Now we have:

                                               [tex]f(x) =- \sqrt{x}+3[/tex]

Lets take [tex]f(x) = -\sqrt{x}+3[/tex] and shift it right for x = 1. That means that instead of x we will have x-1:

                                            [tex]f(x) =- \sqrt{x-1}+3[/tex]

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