Which pair shows equivalent expressions?
2 (two-fifths x + 2) = 2 and two-fifths x + 1
2 (two-fifths x + 2) = four-fifths x + 4
2 (two-fifths x + 4) = Four-fifths x + 2
2 (two-fifths x + 4) = 2 and two-fifths x + 8

Respuesta :

2([tex]\frac{2}{5}[/tex]x + 4) =  [tex]\frac{4}{5}[/tex]x + 4 which is the second option is the equivalent expression.

Explanation:

First,  we need to calculate the value of two-fifths of x. It means 2 portions out of the five portions of x which equates to [tex]\frac{2}{5}[/tex]x.

Now we calculate the values of the two expresssions on the LHS.

1) 2 (two-fifths x + 2) = 2 ([tex]\frac{2}{5}[/tex]x + 2) = [tex]\frac{4}{5}[/tex]x + 4.

2)  (two-fifths x + 4) = 2([tex]\frac{2}{5}[/tex]x + 4) =  [tex]\frac{4}{5}[/tex]x + 8.

Now we determine values of the four expressions on the RHS.

1) Two and two-fifths x + 1 = 2[tex]\frac{2}{5}[/tex]x + 1

2) Four-fifths x + 4 = [tex]\frac{4}{5}[/tex]x + 4

3) Four-fifths x + 2 = [tex]\frac{4}{5}[/tex]x + 2

4) Two and two-fifths x + 8 = 2[tex]\frac{2}{5}[/tex]x + 8.

Out of the various LHS and RHS values, the [tex]1^{st}[/tex] LHS value and [tex]2^{nd}[/tex] RHS value is the same. So option 2 is the answer.

Answer:

second option

Step-by-step explanation: