The chipmunks dropped an acorn from the top of a tree. The acorn was 0.25 kg and had a velocity of 4 m/s when it hit the ground. How much kinetic energy did it have?

Respuesta :

Kinetic energy of the acron had =2 J

Step-by-step explanation:

Given, the chipmunks dropped an acron from the top of a tree. The acron was 0.25 kg and had a velocity of 4 m/s when it hit ground.

Kinetic energy =[tex]\frac{1}{2} m v^2[/tex]

Here m = 0.25 kg and v =4 m/s

Kinetic energy of the acron had =[tex]\frac{1}{2}\times 0.25 \times 4^2[/tex] J

                                                    = 2 J

The kinetic energy of the Chipmunk is 2 Joules.

Kinetic energy is the energy than an object possesses due to its motion. It is given by:

Kinetic Energy(KE) = (1/2)mv²

Where m is mass, v is velocity.

Given that m = 0.25 kg, v = 4 m/s, hence:

KE = (1/2)mv²

KE = (1/2) * 0.25 * 4² = 2J

The kinetic energy of the Chipmunk is 2 Joules.

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