Respuesta :

You need to isolate/get x by itself in the equation

6 + 3(6x - 2) = -12      Distribute/multiply 3 into (6x - 2)

6 + (3)6x - (3)2 = -12

6 + 18x - 6 = -12       Combine like terms (6 and -6)

18x = -12      Divide 18 on both sides to get x by itself

[tex]x = -\frac{12}{18}[/tex]       Simplify

[tex]x=-\frac{2}{3}[/tex]

PROOF

[tex]6+3(6(-\frac{2}{3} )-2)=-12[/tex]           Plug in -2/3 into x, then multiply 6 and -2/3

6 + 3(-4 - 2) = -12         Simplify what's in the parentheses

6 + 3(-6) = -12          Multiply 3 and -6

6 - 18 = -12              

-12 = -12

6 + 3(6x - 2) = -12
6 + 18x - 6 = -12
18x = -12
6x = -4
3x = -2
X = -2/3