Hi, you have not provided the distribution, I'll solve the problem for a particular distribution and you can apply the same method for yours.
Answer:
0.39
Step-by-step explanation:
X is the random event and P(X) is the probability of the event X, therefore, X is the number of televisions
Distribution:
X 0 1 2 3 4 5
P(X) 0.24 0.37 0.20 0.11 0.05 0.03
When they ask for the probability of at least Two televisions, they are asking for the probability that the householder has two or more television or P(X>2). To calculate the probability we need to add the probability of each event in the range:
P(X>2) = P(2) + P(3) + P(4) + P(5) = 0.20 + 0.11 + 0.05 + 0.03 = 0.39
