Increase in temperature is [tex]19.0^{\circ}C[/tex]
Explanation:
When heat is added to a substance, the temperature of the substance increases according to the equation
[tex]Q=mC\Delta T[/tex]
where
Q is the amount of heat supplied
m is the mass of the substance
C is the specific heat capacity of the substance
[tex]\Delta T[/tex] is the change in temperature
For the granite rock in this problem, we have:
[tex]Q=375 kJ = 375,000 J[/tex]
m = 25.0 kg
[tex]C=790 J/kg^{\circ}C[/tex] is the specific heat capacity of granite
And solving for [tex]\Delta T[/tex], we find the increase in temperature:
[tex]\Delta T = \frac{Q}{mC}=\frac{375,000}{(25.0)(790)}=19.0^{\circ}C[/tex]
Learn more about specific heat:
brainly.com/question/3032746
brainly.com/question/4759369
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