The image of distance (di) of the object is 13.33 cm.
Explanation:
Given data in the problem,
The object located at a distance from the convex lens.
do = 40.0 cm
The distance at which the light is focused.
f= 10.0 cm.
We need to find the image of distance di.
The lens equation gives the quantitative relation among the image distance (di), the object distance (do), and the focal length (f).
The equation is given by,
[tex]\frac{1}{f} =\frac{1}{di} +\frac{1}{do}[/tex].
[tex]\frac{1}{10} =\frac{1}{di} +\frac{1}{40}[/tex].
[tex]\frac{1}{10} -\frac{1}{40} =\frac{1}{di}[/tex].
[tex]\frac{4-1}{40}=\frac{1}{di}.\\[/tex]
[tex]\frac{3}{40} = \frac{1}{di}[/tex].
3 di=40.
di=[tex]\frac{40}{3}[/tex].
di = 13.33 cm
The image of distance (di) of the object is 13.33 cm.
