Wastewater from a cement factory contains 0.280 g of Ca2 ion and 0.0550 g of Mg2 ion per 100.0 L of solution. The solution density is 1.001 g/mL. Calculate the Ca2 and Mg2 concentrations in ppm (by mass).

Respuesta :

Answer:

The correct answer is: 2.8 ppm Ca²⁺ and 0.55 ppm Mg²⁺

Explanation:

ppm (by mass) is equal to: mass solute (mg)/mass solution(kg)

First, we use the solution density to calculate the mass of 100.0 L solution in kg:

mass solution= 100.0 L x 1.001 g/ml x 1000 ml/ 1L x 1kg/1000 g= 100.1 kg

Then, we divide the mass of each ion (in mg) into the mass solution to obtain the ppm:

mg Ca²⁺= 0.280 g x 1000 mg/1g= 280 mg

mg Mg²⁺= 0.0550 g x 1000 mg/1g= 55 mg

ppm Ca²⁺= 280 mg Ca²⁺/ 100.1 kg solution= 2.797 mg Ca²⁺/kg solution= 2.8 ppm

ppm Mg²⁺= 55 mg Mg²⁺/ 100.1 kg solution= 0.549 mg Mg²⁺/kg solution= 0.55 ppm