What is the area of this polygon? 28.5 units² 34.5 units² 37.5 units² 40.5 units² 6 sided polygon on a coordinate plane with vertices at (negative 6, negative 2), (negative 5, 1), (negative 1, 4), (1, 1), (5, 3), and (1, negative 2)

Respuesta :

Answer:

Option B.

Step-by-step explanation:

The given vertices of the polygon are (-6,-2),(-5,1),(-1,4),(1,1),(5,3),(1,-2).

We need to find the area of the polygon.

Plot the given vertices and on a coordinate plane and draw the polygon. Divide the polygon in 4 parts as shown below.

Area of rectangle is

[tex]A=length\times width[/tex]

Area of triangle is

[tex]A=\dfrac{1}{2}\times base\times height[/tex]

Area of each figure is

[tex]A_1=\dfrac{1}{2}\times 1\times 3=1.5[/tex]

[tex]A_2=\dfrac{1}{2}\times 6\times 3=9[/tex]

[tex]A_3=\dfrac{1}{2}\times 4\times 3=6[/tex]

[tex]A_4=6\times 3=18[/tex]

Area of polygon is

[tex]A=A_1+A_2+A_3+A_4[/tex]

[tex]A=1.5+9+6+18=34.5[/tex]

The area of polygon is 34.5 units².

Therefore, the correct option is B.

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