A colony of bacteria originally contains 200 bacteria. It doubles in size every 30 minutes. How many hours will it take for the colony to contain 2,000 bacteria? (Round your answer to one decimal place.)

Respuesta :

Answer:

It will take 1.7 hours for the colony to contain 2,000 bacteria.

Explanation:

One bacteria divides into two by the process of binary fission.

Initial bacteria population = 200

Growth factor = 2

It doubles in size every 30 minutes.

Time = t/30

The exponential growth function is

[tex]y=ab^x[/tex]

where, a is initial value, b is growth factor and x is time.

Substitute a=200, b=2 and [tex]x=\frac{t}{30}[/tex] in the above function.

[tex]y=200(2)^{\frac{t}{30}[/tex]

We need to find the time taken by bacteria to reach 2,000 bacteria.

Substitute y=2000 in the above equation.

[tex]2000=200(2)^{\frac{t}{30}[/tex]

Divide both sides by 200.

[tex]10=(2)^{\frac{t}{30}}[/tex]

Taking log both sides.

[tex]\log 10=\log (2)^{\frac{t}{30}}[/tex]

[tex]1=\frac{t}{30}\log (2)[/tex]

[tex]30=\log 2(t)[/tex]

Divide both sides by log 2.

[tex]\dfrac{30}{\log 2}=t[/tex]

[tex]\dfrac{30}{0.301}=t[/tex]

[tex]99.667774=t[/tex]

It will take 99.66774 minutes for the colony to contain 2,000 bacteria.

1 hour = 60 minute

[tex]t=\dfrac{99.667774}{60}=1.66112\approx 1.7[/tex]

Therefore, it will take 1.7 hours for the colony to contain 2,000 bacteria.