Answer: The new water level when silver metal is submerged is 18.24 mL
Explanation:
We are given:
Volume of graduated cylinder = 15.0 mL
To calculate volume of a substance, we use the equation:
[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex]
Density of silver metal = 10.5 g/mL
Mass of silver metal = 34.0 g
Putting values in above equation, we get:
[tex]10.5g/mL=\frac{34.0g}{\text{Volume of silver metal}}\\\\\text{Volume of silver metal}=\frac{34.0g}{10.5g/mL}=3.24mL[/tex]
New water level = Volume of silver metal + Volume of graduated cylinder
New water level = (3.24 + 15.0) mL = 18.24 mL
Hence, the new water level when silver metal is submerged is 18.24 mL
