Respuesta :
Answer: The molality of potassium hydroxide solution is 0.608 m
Explanation:
We are given:
3.301 mass % of potassium hydroxide solution.
This means that 3.301 grams of potassium hydroxide is present in 100 grams of solution
Mass of solvent = Mass of solution - Mass of solute (KOH)
Mass of solvent = (100 - 3.301) g = 96.699 g
To calculate the molality of solution, we use the equation:
[tex]\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams})}[/tex]
Where,
[tex]m_{solute}[/tex] = Given mass of solute (KOH) = 3.301 g
[tex]M_{solute}[/tex] = Molar mass of solute (KOH) = 56.1 g/mol
[tex]W_{solvent}[/tex] = Mass of solvent = 96.699 g
Putting values in above equation, we get:
[tex]\text{Molality of KOH}=\frac{3.301\times 1000}{56.1\times 96.699}\\\\\text{Molality of KOH}=0.608m[/tex]
Hence, the molality of potassium hydroxide solution is 0.608 m
