Explanation:
Formula to calculate resistivity is as follows.
[tex]\rho = \frac{1}{qN \mu}[/tex]
= [tex]\frac{1}{(1.6 \times 10^{-19}) \times 2.72 \times 10^{17} \times 3900}[/tex] ohm/cm
= [tex]5.89 \times 10^{-3} ohm/cm[/tex]
As germanium is an intrinsic conductor. Hence, resistivity of Ge is as follows.
[tex]\rho_{1} = \frac{1}{2qN_{o}\sqrt{\mu_{e}\mu_{r}}}[/tex]
= [tex]\frac{1}{2q(N_{A})^{\frac{1}{2}}\sqrt{\mu_{e}\mu_{r}}}[/tex]
= [tex]\frac{1}{2 \times (1.6 \times 10^{-19}) \times (\sqrt{4.42 \times 10^{22}})\sqrt{(3900)(1900)}}[/tex] ohm/cm
= 0.546 [tex]ohm (\mu m)^{-1}[/tex]
Thus, we can conclude that resistivity of the Ge is 0.546 [tex]ohm (\mu m)^{-1}[/tex].
