Answer:
[tex]a = - \frac{3}{4}[/tex]
Step-by-step explanation:
The correct solution of the given equation is as follows :
We have,
[tex]\frac{1}{64} = 16^{2a}[/tex]
⇒ [tex]4^{- 3} = (2^{4} )^{2a}[/tex]
⇒ [tex]2^{(2 \times (-3))} = 2^{8a}[/tex]
⇒ [tex]2^{- 6} = 2^{8a}[/tex]
Comparing the power of equal base, we get
- 6 = 8a
⇒ [tex]a = - \frac{6}{8}[/tex]
⇒ [tex]a = - \frac{3}{4}[/tex]
Therefore, before equating the powers of two terms the base of the terms should be equal and here this is the error. (Answer)
Answer:
The bases were not the same when the exponents were set equal to each other.
16 should have been written as 4 squared.
The exponent on the right should be 4a instead of 8a.
The correct solution is a= -3/4
Step-by-step explanation:
According to Edgu.
