Respuesta :
Answer:
195.2 × 10⁻¹⁹ J.
Explanation:
The relation between the work done, potential difference and charge is as follows;
V = w / q.
Here, the potential difference, V = 122mV and q is the charge = 1.6 × 10⁻¹⁹ C
Substitute these values to find the amount of work done
W = v × q
W = 122 × 1.6 × 10⁻¹⁹
W = 195.2 × 10⁻¹⁹ J
Thus, the answer is 195.2 × 10⁻¹⁹ J.
Answer:
[tex]W = 1.95 * 10^{-20}[/tex] J
Explanation:
The potential on the inner side of the membrane is [tex]0[/tex]mV
And the potential on the outer side of the membrane is [tex]122[/tex] mV
So the potential difference across the inner and outer membrane is equal to [tex]122[/tex] mV
We know that work done is equal to
[tex]W = q . V\\[/tex]
Where, q represents the charge of the particle and
V represents the potential difference across the inner and outer membrane
Substituting the given values in above equation, we get -
[tex]W = 1.6 * 10^{-19} * 122 * 10^{-3}\\W = 195.2 * 10^ {-22}[/tex]
[tex]W = 1.95 * 10^{-20}[/tex] J
