Respuesta :
Answer:
(a). The maximum loss of water vapor by the person is [tex]8.8\times10^{-2}\ g[/tex]
(b). The partial pressure of water vapor is [tex]6.29\times10^{3}\ N/m^2[/tex]
Explanation:
Given that,
Temperature = 37.0°C
Volume of air = 2.00 L
Density of vapor = 44.0 g/m³
We need to calculate the maximum loss of water vapor by the person
Using formula of density
[tex]m=\rho_{air}\times V_{air}[/tex]
Put the value into the formula
[tex]m=44.0\times2.00\times10^{-3}[/tex]
[tex]m=0.088\ g[/tex]
[tex]m=8.8\times10^{-2}\ g[/tex]
(b). We need to calculate the partial pressure of water vapor
Using formula of pressure
[tex]PV=nRT[/tex]
[tex]P=\dfrac{nRT}{V}[/tex]
[tex]P=\dfrac{\rho\times R\times T}{M}[/tex]
Put the value into the formula
[tex]P=\dfrac{44\times8.314\times(37+273)}{18.01528}[/tex]
[tex]P=6294.82\ N/m^2[/tex]
[tex]P=6.29\times10^{3}\ N/m^2[/tex]
Hence, (a). The maximum loss of water vapor by the person is [tex]8.8\times10^{-2}\ g[/tex]
(b). The partial pressure of water vapor is [tex]6.29\times10^{3}\ N/m^2[/tex]
