Draw an orbital diagram showing valence electrons, and write the condensed ground-state electron configuration for each:
(a) Ga (b) Zn (c) Sc

Respuesta :

Answer : The condensed ground-state electron configuration for each is:

(a) [tex][Ar]4s^24p^{1}[/tex]

(b) [tex][Ar]4s^23d^{10}[/tex]

(c) [tex][Ar]4s^23d^{1}[/tex]

Explanation :

Electronic configuration : It is defined as the representation of electrons around the nucleus of an atom.

Number of electrons in an atom are determined by the electronic configuration.

Noble-Gas notation : It is defined as the representation of electron configuration of an element by using the noble gas directly before the element on the periodic table.

(a) The given element is, Ga (Gallium)

As we know that the gallium element belongs to group 13 and the atomic number is, 31

The ground-state electron configuration of Ga is:

[tex]1s^22s^22p^63s^23p^64s^23d^{10}4p^1[/tex]

So, the condensed ground-state electron configuration of Ga in noble gas notation will be:

[tex][Ar]4s^24p^{1}[/tex]

(b) The given element is, Zn (Zinc)

As we know that the zinc element belongs to group 12 and the atomic number is, 30

The ground-state electron configuration of Zn is:

[tex]1s^22s^22p^63s^23p^64s^23d^{10}[/tex]

So, the condensed ground-state electron configuration of Zn in noble gas notation will be:

[tex][Ar]4s^23d^{10}[/tex]

(c) The given element is, Sc (Scandium)

As we know that the scandium element belongs to group 3 and the atomic number is, 21

The ground-state electron configuration of Sc is:

[tex]1s^22s^22p^63s^23p^64s^23d^{1}[/tex]

So, the condensed ground-state electron configuration of Sc in noble gas notation will be:

[tex][Ar]4s^23d^{1}[/tex]

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