Answer:
Explanation:
Given
mass of vehicle [tex]m=1500\ kg[/tex]
Speed of vehicle [tex]u=50\ km/hr\approx 13.89\ m/s[/tex]
Kinetic Energy Possessed by mass
[tex]K_i=\frac{1}{2}mu^2[/tex]
[tex]K_i=\frac{1}{2}\times 1500\times (13.89)^2[/tex]
[tex]K_i=144.69\ kJ[/tex]
when vehicle is slowed down to speed of [tex]v=10\ km/hr\approx 2.78\ m/s[/tex]
Kinetic Energy at this speed
[tex]K_f=\frac{1}{2}mv^2[/tex]
[tex]K_f=\frac{1}{2}\times 1500\times (2.78)^2[/tex]
[tex]K_f=5.78\ kJ[/tex]
Energy Recovered [tex]=K_i-K_f[/tex]
Energy Recovered[tex]=144.69-5.78=138.9\ kJ[/tex]
