Respuesta :

meerkat18
The given expression, 81a^6 - 100, is a difference of two squares. The first term 81a^6 is a square of 9a³. The second term, 100, is a square of 10. The factors of the given expression is therefore, (9a³ - 10) x (9a³ + 10).
JeanaShupp

Answer:The factorization of [tex]81a^6-100=(9a^3+10)(9a^3-10)[/tex]


Step-by-step explanation:

Given algebraic expression:[tex]81a^6-100[/tex]

This can be written in the form of square as [tex](9a^3)^2-10^2[/tex]

By using identity, [tex]a^2-b^2=(a+b)(a-b)[/tex] , the above polynomial can be rewritten as

[tex](9a^3)^2-10^2=(9a^3+10)(9a^3-10)[/tex]

Therefore the factorization of [tex]81a^6-100=(9a^3+10)(9a^3-10)[/tex]


Otras preguntas