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A 4 kg block slides down a rough inclined plane inclined at 30° 179009.GIF with the horizontal. Determine the coefficient of kinetic friction between the block and the surface if the block has an acceleration of 1.2 m/s2.

Respuesta :

janmejaysinha4
F=ma
F= 4x1.2
F= 4.8 N

F= 4gsin30 - Friction
Friction= 19.6 - 4.8 N
Friction= 14.8 N

Friction= u x 4gcos30
14.8 / 4gcos30 = u
u= 0.43596...
u= 0.44

coefficient is 0.44

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