A savings account earns 8% interest each year, compounded quarterly (4 times a year). If a person invests $100 and make no further deposits or withdrawals, what is the balance in the account after 3 years ​

Respuesta :

The balance in account after 3 years is $ 126.82

Solution:

The formula for compound interest, including principal sum, is:

[tex]A = p(1+\frac{r}{n})^{nt}[/tex]

Where,

A = the future value of the investment

P = the principal investment amount

r = the annual interest rate (decimal)

n = the number of times that interest is compounded per unit t

t = the time the money is invested

From given,

p = 100

t = 3 years

r = 8 % = 8/100 = 0.08

n = 4 times

Therefore,

[tex]A = 100(1 + \frac{0.08}{4})^{4 \times 3}\\\\A = 100( 1 + 0.02)^{12}\\\\A = 100(1.02)^{12}\\\\A = 100 \times 1.2682\\\\A = 126.82[/tex]

Thus the balance in account after 3 years is $ 126.82

The balance in the account after 3 year is $126.82

Compound interest

  • A = P(1 + r/n)ⁿˣ

where

A = amount

P = principal = $100

r = rate = 8% = 8 / 100 = 0.08

x = time

Therefore,

A = 100 (1 + 0.08 / 4)⁴⁽³⁾

A = 100(1.02)¹²

A = 100 × 1.26824179456

A = 126.824179456

A = $126.82

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