contestada

Tim wrote the expressions g^2-2gh-h^2 and -g(g+2h-1) -h^2. He substituted 0 for g and 1 for h, and said the expressions are equivalent. Is he correct? Explain.

Respuesta :

Answer

Yes. The result both gives -1.

Step-by-step explanation:

The expressions are [tex]g^2-2gh-h^2[/tex] and [tex]-g(g+2h-1) -h^2[/tex]

If he substituted  g=0 and h=1

[tex]g^2-2gh-h^2=0^2-(2X0X1)-1^2=0-0-1=-1[/tex]

[tex]-g(g+2h-1) -h^2=-0(0+(2X1)-1)-1^2=0-1=-1[/tex]

[tex]-1^2=-1 and 0X a=0[/tex]

The result both gives -1.

Otras preguntas