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What is the equation of the graph below?

On a coordinate plane, a curve crosses the y-axis at (0, negative 1). It has a minimum of negative 1 and a maximum of 1. It goes through 1 cycle at 2 pi.
y = cosine (x + StartFraction pi Over 2 EndFraction)
y = cosine (x + 2 pi) y = cosine (x + StartFraction pi Over 3 EndFraction)
y = cosine (x + pi)

What is the equation of the graph below On a coordinate plane a curve crosses the yaxis at 0 negative 1 It has a minimum of negative 1 and a maximum of 1 It goe class=

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Answer:

[tex]y=cos(x + \pi)[/tex]

Step-by-step explanation:

Remember that the cosine function has a period of 2π.

Now, the parental function is [tex]y=cosx[/tex], which has y-intercept at y = 1, and x-intercept at π/2.

Notice that the function showed in the graph attached has y-intercept at y = -1 and x-intercept at π/2. This indicates that the function has been moved leftwards π units.

Therefore, the function that belongs to this graph is

[tex]y=cos(x + \pi)[/tex]

adioabiola

The equation of the given graph is; y = cosine (x + pi)

Equation of cosine graphs

By convention, the cosine function like most other trigonometric functions has a period of 2π.

Since, the parental function is y = cos x, which has y-intercept at y = 1, and x-intercept at π/2.

From observation, the function showed in the graph attached has y-intercept at y = -1 and x-intercept at π/2.

This can be interpreted to mean that the function has been translated leftwards π units.

Ultimately, the function that belongs to this graph is; y = cosine (x + pi)

Read more on cosine graphs;

https://brainly.com/question/17075439

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