Respuesta :
The sequence 5'TTATAA3' 3' AATATT 5' will be recognized by the Aan 1 enzyme and blunt ends can be produced.
Explanation:
In prokaryotes the restriction enzyme and restriction sites are seen. Restriction enzyme will either produce a sticky end as eco R1 or blunt end. The single strand of DNA will have overhangs which can combine with the other strand by complementary base pairing and ligase enzyme to get replicated.
The recognition sequence 5'TTATAA3' 3' AATATT 5' is present in AaRl enzyme. The cut will be blunt.
5' ---TTA TAA--- 3'
3' ---AAT ATT--- 5'
Restriction enzymes are used in recombinant DNA technology.
The restriction enzymes are the endonucleases that are found in the prokaryotes and cleave a DNA sequence in a specific manner. They are present as a part of the defense mechanism in bacteria and archaea.
The correct answer is:
5'TTATAA3' 3' AATATT 5'
This can be explained as:
- This sequence can be recognized by the Arthrobacter aurescens RFL 2 bacteria.
- The restriction enzymes will either create a blunt end or a sticky end.
- The spliced DNA strands will have overhang sequences that can be ligated with other sequences.
- The recognition site is present in the AaRI and will cleave the sequence into blunts as follows:
5' ---TTA TAA--- 3'
3' ---AAT ATT--- 5'
Therefore, the restriction enzyme will cleave blunt or sticky ends.
To learn more about restriction enzymes follow the link:
https://brainly.com/question/13532104
