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The circle below is centered at the point (2, -1) and has a radius of length 3.
What is its equation?
32
O A. (x-2)2 + (y+ 1)2 =
O B. (x + 2)2 + (x-1)2 =
32
O C. (x + 1)2 + (y-2)2 = 9
O D. (x-1)2 + (y + 2)2 = 9

Respuesta :

bhuvna789456

Equation of the circle is (x - 2)² + (y + 1)² = 9

Step-by-step explanation:

  • Step 1: Equation of a circle is of the form (x - h)² + (y - k)² = r² where (h,k) is the coordinates of the center of the circle. Here, center is (2, -1) and radius is 3.

⇒ (x - 2)² + (y + 1)² = 9

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