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It is recommended that 7.1 mL of Grow-It-Right plant food be mixed with 2 L of water for
feeding house plants. How much plant food should be mixed with 1 gal of water to maintain the
same concentration? (1 gal = 3.8 L.) Express the answer in milliliters. Round the answer to two
decimal places.​

Respuesta :

Answer:

To maintain the concentration, 13.49 mL of Grow-It-Right plant food must be added to 1 gal of water.

Explanation:

The instructions call for mixing 7.1 mL of Grow-It-Right plant food with 2 L of water for  fertilizing house plants.

In fertilizing plants, specific nutrients, essential minerals and other growth improving factors are added to the plant's soil in order to improve the health or yield of the plant. Often, these are concentrated and require dilution, where certain amounts are mixed with water before application.

1 gal of water to maintain the  same concentration? (1 gal = 3.8 L)

Dilutions are calculated from the equation:

[tex]C_{1} V_{1} =C_{2} V_{2}[/tex]

where,

[tex]C_{1}[/tex], the initial concentration

[tex]V_{1}[/tex], the initial volume

[tex]C_{2}[/tex], the final concentration

[tex]V_{2}[/tex], the  final  volume

Since the concentration is constant, a dilution factor should be calculated. The dilution factor is a factor by which the stock is diluted. I t can be calculated from

[tex]\frac{V_{2} }{V_{1} }[/tex]

...converted, 1 gal water= 3.8 L

∴ Substituting into the equation...

The dilution factor= [tex]\frac{3.8 L}{2 L}[/tex] = 1.9

∴ For  1 gal of water =  1.9 × 7.1 mL =  13.49 mL of Grow-It-Right plant food must be added