If a person of mass 80 kg jumps onto a trampoline, having a speed of 10 m/s in the very moment of touching it, how much force would the trampoline exert onto the person if it stops the fall within 1.6 s?

Respuesta :

Answer:500N

Explanation:

f=m(v-u)/t

F=80(0-(-10))/1.6

F=80(10)/1.6

F=800/1.6

F=500N