The solution set is [tex]\{-5,5\}[/tex]
Explanation:
The given equation is [tex]a^{2}-3=22[/tex]
To determine the solution set of the equation, let us solve the equation.
Adding both sides of the equation by 3, we have,
[tex]a^2=25[/tex]
Taking square root on both sides of the equation, we get,
[tex]a=\sqrt{25}, a=-\sqrt{25}[/tex]
[tex]a=5, a=-5[/tex]
Thus, the solution of the equation is [tex]a=5, a=-5[/tex]
The solution set of the equation is the set which contains all the solutions of the equations.
Thus, writing the solutions of the equation using set notation, we have,
[tex]\{-5,5\}[/tex]
Thus, the solution set is [tex]\{-5,5\}[/tex]
