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8-- A ball moves with a constant speed of 48 m/s around a circle of radius 4 m. What is the
period of the motion?(use O=3 )

Respuesta :

The period of motion is 0.52 seconds

Solution:

Given that,

speed = 48 m/s

radius = 4 m

Find the circumference of circle

[tex]C = 2 \pi r\\\\C = 2 \times 3.14 \times 4\\\\C = 25.12[/tex]

Find the period of motion

[tex]V = \frac{2 \pi r}{T}\\\\48 = \frac{25.12}{T}\\\\T = \frac{25.12}{48}\\\\T = 0.5233 \approx 0.52[/tex]

Thus period of motion is 0.52 seconds

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